Does C Utilize Short-Circuit Evaluation with the && Operator?**
In C , when encountering an expression such as (bool1 &**&** bool2), does the language evaluate both bool1 and bool2 regardless of the value of bool1?
Answer:
No, C employs short-circuit evaluation for the && operator. If bool1 is evaluated as false, the evaluation of bool2 is skipped.
Short-circuit evaluation is a mechanism in programming languages that optimizes boolean expressions by only evaluating the second operand if the first operand meets a specific condition (false in the case of &&). This prevents unnecessary calculations and improves code efficiency.
The same principle applies to the || operator. If bool1 evaluates to true, the entire expression is true, and bool2 is not evaluated.
If you explicitly want to evaluate both expressions, you can use the & and | operators instead of && and ||.
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