Home > Backend Development > C++ > How Can I Generically Test if a String Can Be Parsed to a Specific Type?

How Can I Generically Test if a String Can Be Parsed to a Specific Type?

Susan Sarandon
Release: 2024-12-30 19:05:16
Original
346 people have browsed it

How Can I Generically Test if a String Can Be Parsed to a Specific Type?

Generically Testing Strings with TryParse

In an attempt to create a generic extension method for verifying string values, you encountered an issue with 'TryParse' not being defined in any interface and sought an alternative solution.

Alternative Approach Using TypeDescriptor

The TypeDescriptor class provides a way to retrieve a type converter for a given data type. This converter can be used to convert strings to and from other types. Here's an updated version of your code:

public static bool Is(this string input, Type targetType)
{
    try
    {
        TypeDescriptor.GetConverter(targetType).ConvertFromString(input);
        return true;
    }
    catch
    {
        return false;
    }
}
Copy after login

In this version, you can pass any target type, and it will attempt to convert the string to that type using the appropriate converter. If the conversion succeeds, the method returns true; otherwise, it returns false.

Exceptions and Alternatives

While the exception-based approach works, you may prefer a more robust option. Instead of using exceptions, you could return a Nullable value, indicating whether the conversion was successful.

Alternatively, you could create overloads for common types, such as int, double, and DateTime, and define custom logic for each type. This would eliminate the need for a generic implementation and provide more efficient and type-safe conversions.

The above is the detailed content of How Can I Generically Test if a String Can Be Parsed to a Specific Type?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template