Home > Database > Mysql Tutorial > How to Correctly Pass Parameters to ADO.NET INSERT Commands?

How to Correctly Pass Parameters to ADO.NET INSERT Commands?

Patricia Arquette
Release: 2024-12-30 20:07:19
Original
234 people have browsed it

How to Correctly Pass Parameters to ADO.NET INSERT Commands?

Passing Parameters to ADO.NET Commands

In order to insert a record into a database using an ADO.NET command, parameters should be utilized. The example provided faces an issue due to an incomplete implementation:

SqlCommand comand = new SqlCommand("INSERT INTO Product_table Values(@Product_Name,@Product_Price,@Product_Profit,@p)", connect);
SqlParameter ppar = new SqlParameter();
ppar.ParameterName = "@Product_Name";
ppar.Value = textBox1.Text;
MessageBox.Show("Done");
comaand.Parameters.Add(ppar);
Copy after login

To resolve this issue and correctly add parameters, follow these steps:

SqlCommand cmd = new SqlCommand("INSERT INTO Product_table Values(@Product_Name, @Product_Price, @Product_Profit, @p)", connect);
cmd.Parameters.Add("@Product_Name", SqlDbType.NVarChar, ProductNameSizeHere).Value = txtProductName.Text;
cmd.Parameters.Add("@Product_Price", SqlDbType.Int).Value = txtProductPrice.Text;
cmd.Parameters.Add("@Product_Profit", SqlDbType.Int).Value = txtProductProfit.Text;
cmd.Parameters.Add("@p", SqlDbType.NVarChar, PSizeHere).Value = txtP.Text;
cmd.ExecuteNonQuery();
Copy after login

In this code:

  • Provide the column names before the values in the INSERT statement.
  • Specify the data type of each parameter using SqlDbType.
  • Set the maximum size for parameters with variable-length data types.
  • Avoid using AddWithValue as it can lead to security vulnerabilities.

This approach ensures that parameters are properly added to the command and the record is successfully inserted into the database.

The above is the detailed content of How to Correctly Pass Parameters to ADO.NET INSERT Commands?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template