List Comprehension:
It's a syntactically elegant method to create or manipulate lists in a single line of code.
Write a program to print the fruits contains letter 'a'(using for loop):
fruits = ["apple", "banana", "cherry", "kiwi", "mango"] newlist = [] for x in fruits: if "a" in x: newlist.append(x) print(newlist)
['apple', 'banana', 'mango']
(Using list comprehension):
fruits = ["apple", "banana", "cherry", "kiwi", "mango"] newlist = [x for x in fruits if "a" in x] print(newlist)
['apple', 'banana', 'mango']
Write a program to find the square root of given number:
l = [10,20,30,40] newlist = [] #using for loop for num in l: newlist.append(num**2) print(newlist) #using loop in comprehensive way newlist = [num**2 for num in l] print(newlist)
[100, 400, 900, 1600] [100, 400, 900, 1600]
Find similar numbers from 2 lists and different numbers from the same 2 lists:
l1 = [10,20,30,40] l2 = [30,40,50,60] #for loop for num in l1: for no in l2: if num== no: print(num,end=' ') #comprehensive print([num for num in l1 for no in l2 if num==no])
30 40 [30, 40]
1 = [10,20,30,40] l2 = [30,40,50,60] #comprehensive output = [num for num in l1 if num not in l2] output = output + [num for num in l2 if num not in l1] print(output) #for loop for num in l1: if num not in l2: print(num,end=' ') for num in l2: if num not in l1: print(num,end=' ')
[10, 20, 50, 60] 10 20 50 60
Write a program for the given output in comprehensive approach:
l1 = [1,2,3]
l2 = [5,6,7]
Output:[(1, 5), (1, 6), (1, 7), (2, 5), (2, 6), (2, 7), (3, 5), (3, 6), (3, 7)]
l1 = [1,2,3] l2 = [5,6,7] l = [(i,j) for i in l1 for j in l2 if i!=j] print(l)
[(1, 5), (1, 6), (1, 7), (2, 5), (2, 6), (2, 7), (3, 5), (3, 6), (3, 7)]
Write a program for the given output:
s = "a1b2c3"
output: abc123
Method:1
s= "a1b2c3" alpha_list = [] num_list = [] for letter in s: if letter.isalpha(): alpha_list.append(letter) else: num_list.append(letter) print("".join(alpha_list+num_list))
Method:2
s = "a1b2c3" letter=''.join([i for i in s if i.isalpha()]) no=''.join([i for i in s if i.isdigit()]) print(letter+no)
abc123
Write a program for the given output:
s = "a4k3b2"
output: aeknbd
s = "a4k3b2" i = 0 while i<len(s): first = s[i] second = int(s[i+1]) print(first, chr(ord(first)+second),sep='',end='') i+=2
aeknbd
Task:
1) Write a program to get the output 'abbbbklllbcc'
s = "a4k3b2" i = 0 while i < len(s): first = s[i] second =int(s[i + 1]) print(first,chr(ord(first)+1)*second,sep='',end='') i+=2
abbbbklllbcc
2) Write a program to get the output 'aaaaakkkkbbb'
s = "a4k3b2" i = 0 while i < len(s): first = s[i] second =int(s[i + 1]) print(first,chr(ord(first))*second,sep='',end='') i+=2
aaaaakkkkbbb
3.Join the given matrix into single list using comprehensive for and normal for loop.
Method:1(Using for loop)
matrix = [[10,20,30], [40,50,60], [70,80,90]] output=[] for i in matrix: for j in i: output.append(j) print(output)
Method:2(Using comprehensive for loop)
matrix = [[10, 20, 30], [40, 50, 60], [70, 80, 90]] output = [j for i in matrix for j in i] print(output)
[10, 20, 30, 40, 50, 60, 70, 80, 90]
4.l = ['ABC','DEF', 'GHI', 'JKL']
Get OUTPUT: ['ABC', 'def','GHI', 'jkl']
l = ['ABC', 'DEF', 'GHI', 'JKL'] output = [] for i, alpha in enumerate(l): if i % 2 != 0: output.append(alpha.casefold()) else: output.append(alpha) print(output)
['ABC', 'def', 'GHI', 'jkl']
5.Find the row wise total for the given matrix:
matrix = [[10,20,30], [40,50,60], [70,80,90]] for inner in matrix: total = 0 for index,num in enumerate(inner): total+=num print(total,end=' ')
60 150 240
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