How Can I Execute Multiple SQL Files in a Single Command?

Executing Multiple SQL Files in a Single Command

When managing an SQL Server database, it's often necessary to apply changes from multiple external SQL files. While it's possible to execute each file individually, this process can become tedious and time-consuming. This article presents an efficient solution to run all SQL files in a directory with a single command.

Step 1: Create a Batch File (.BAT)

Create a text file (.txt) with the following content:

for %%G in (*.sql) do sqlcmd /S servername /d databaseName -E -i"%%G"
pause

Replace "servername" and "databaseName" with the appropriate values for your database.

Step 2: Save as Batch File

Save the text file as a batch file with a ".bat" extension. For example, name it "run_sql.bat".

Step 3: Execute the Batch File

Place the batch file in the directory containing the SQL files you want to execute. Double-click the batch file to run it.

Additional Options:

• Provide Credentials: If you need to specify a username and password, replace "-E" with "-U username -P password":

for %%G in (*.sql) do sqlcmd /S servername /d databaseName -U username -P password -i"%%G"

• Ignore Errors: To continue executing even if an error occurs in one of the SQL files, add "-b" to the sqlcmd command:

for %%G in (*.sql) do sqlcmd /S servername /d databaseName -E -b -i"%%G"

Conclusion:

This batch file simplifies the execution of multiple SQL files in one go. By specifying the appropriate database parameters and processing options, you can efficiently update or modify your database with ease.

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