Retrieving Last N Elements of a Collection Using LINQ
In LINQ, obtaining the last N elements of a collection can be achieved with a combination of Skip() and Count() methods. The Skip() method allows you to skip a specified number of elements from the beginning of a collection, while Count() returns the total number of elements in the collection.
To obtain the last N elements, we can determine the total count of the collection and subtract N from it. The resulting value is then passed to Skip() to skip the first (count - N) elements, leaving only the last N elements. This can be expressed as:
collection.Skip(Math.Max(0, collection.Count() - N));
This approach effectively allows element order to be preserved without requiring sorting. It also ensures compatibility across multiple LINQ providers.
Extension Method Implementation
Here is an extension method implementation for TakeLast(int N) that utilizes the above approach:
public static class MiscExtensions { public static IEnumerable<T> TakeLast<T>(this IEnumerable<T> source, int N) { return source.Skip(Math.Max(0, source.Count() - N)); } }
This extension method can be used as follows:
collection.TakeLast(5);
Performance Considerations
While this approach is generally efficient, it's worth considering the impact of calling Count() on certain data structures. In some cases, this can result in the enumeration of the entire data structure. Performance can be further optimized in situations where a forward-only enumerable is required and multiple passes over the data need to be avoided. Alternative one-pass algorithms that utilize temporary buffers can be employed for such cases.
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