How Can I Replace Whole Words in a String Using Regular Expressions or VB's Replace Method?

Replacing Whole Words in Strings

In string manipulation tasks, it may be necessary to replace whole words rather than partial matches. This can be achieved using various approaches, one of which is regular expressions.

Regular Expression Approach

C#:

string input = "test, and test but not testing.  But yes to test";
string pattern = @"\btest\b";
string replace = "text";
string result = Regex.Replace(input, pattern, replace);
Console.WriteLine(result);

VB:

Dim input As String = "test, and test but not testing.  But yes to test"
Dim pattern As String = "\btest\b"
Dim replace As String = "text"
Dim result As String = Regex.Replace(input, pattern, replace)
Debug.WriteLine(result)

In this approach, the regular expression pattern @"btestb" matches the word "test" within word boundaries, where b denotes a word boundary. The replace string is then substituted for the matched portions.

VB-Specific Method

VB:

Dim input As String = "test, and test but not testing.  But yes to test"
Dim result As String = input.Replace(" test ", " text ")
Debug.WriteLine(result)

In VB, the Replace method can be utilized to replace a specific word. By adding spaces around the word to find, it ensures that only whole words are matched and replaced.

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