Home > Java > javaTutorial > How to Get the Current Date and Time in 'dd/MM/yyyy HH:mm:ss.SS' Format in Java?

How to Get the Current Date and Time in 'dd/MM/yyyy HH:mm:ss.SS' Format in Java?

Patricia Arquette
Release: 2025-01-04 13:38:39
Original
637 people have browsed it

How to Get the Current Date and Time in

How to Obtain the Current Date and Time in "dd/MM/yyyy HH:mm:ss.SS" Format

To retrieve the current date and time in the specified format "dd/MM/yyyy HH:mm:ss.SS," you can utilize the following code:

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public class DateAndTime {

    public static void main(String[] args) throws Exception {
        Calendar cal = Calendar.getInstance();
        SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss.SS");
        String strDate = sdf.format(cal.getTime());
        System.out.println("Current date in String Format: " + strDate);

        SimpleDateFormat sdf1 = new SimpleDateFormat();
        sdf1.applyPattern("dd/MM/yyyy HH:mm:ss.SS");
        Date date = sdf1.parse(strDate);
        System.out.println("Current date in Date Format: " + date);
    }
}
Copy after login

This code employs the SimpleDateFormat class to specify the desired date and time format. It leverages the Calendar class to obtain the current date and time, then formats it using the specified format.

Additional Information

If you encounter an output where the date is displayed in a different format within the Date Format output, you can resolve this by invoking the following line prior to formatting the Date object:

sdf1.setDateFormatSymbols(new SimpleDateFormat("dd/MM/yyyy HH:mm:ss.SS").getDateFormatSymbols());
Copy after login

This ensures that SimpleDateFormat utilizes the same date and time format symbols for both the string and date formatting processes.

The above is the detailed content of How to Get the Current Date and Time in 'dd/MM/yyyy HH:mm:ss.SS' Format in Java?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template