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How to Create Type-Safe Discriminated Unions (Tagged Unions) in C#?

Susan Sarandon
Release: 2025-01-04 16:11:40
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How to Create Type-Safe Discriminated Unions (Tagged Unions) in C#?

Discriminating Union in C#

Question:

How to create a discriminating union in C# (also called tagged union)? This union allows different types to be used to represent a single value and provides compile-time type safety.

Answer:

Using generic type parameter constraints, you can create type-safe discerning unions. The following code demonstrates how to create a discriminating union with three cases (int, char, and string):

public abstract class Union3<A, B, C>
{
    public abstract T Match<T>(Func<A, T> f, Func<B, T> g, Func<C, T> h);
    private Union3() { }

    public sealed class Case1 : Union3<A, B, C>
    {
        public readonly A Item;
        public Case1(A item) : base() { this.Item = item; }
        public override T Match<T>(Func<A, T> f, Func<B, T> g, Func<C, T> h)
        {
            return f(Item);
        }
    }

    public sealed class Case2 : Union3<A, B, C>
    {
        public readonly B Item;
        public Case2(B item) { this.Item = item; }
        public override T Match<T>(Func<A, T> f, Func<B, T> g, Func<C, T> h)
        {
            return g(Item);
        }
    }

    public sealed class Case3 : Union3<A, B, C>
    {
        public readonly C Item;
        public Case3(C item) { this.Item = item; }
        public override T Match<T>(Func<A, T> f, Func<B, T> g, Func<C, T> h)
        {
            return h(Item);
        }
    }
}
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To create an instance of the discriminating union, use a static factory method to specify the corresponding case and provide value. For example:

Union3<int, char, string> union1 = Union3<int, char, string>.Case1(5);
Union3<int, char, string> union2 = Union3<int, char, string>.Case2('x');
Union3<int, char, string> union3 = Union3<int, char, string>.Case3("Juliet");
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By using the Match method, you can safely access the value of the union on a specific case basis. For example:

string value1 = union1.Match(num => num.ToString(), character => new string(new char[] { character }), word => word);
string value2 = union2.Match(num => num.ToString(), character => new string(new char[] { character }), word => word);
string value3 = union3.Match(num => num.ToString(), character => new string(new char[] { character }), word => word);
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This method uses compile-time type checking to ensure that the correct function is provided for the given case. The compiler will throw an error if you try to access a value that does not match the case.

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