


How to Build a Generic CRUD Controller in Laravel for Multiple Resources
How to Build a Generic CRUD Controller in Laravel for Multiple Resources
Managing multiple CRUD operations in a Laravel application can be overwhelming, especially when handling a growing number of models. In this post, I'll guide you on creating a generic CRUD controller that allows you to handle existing and future CRUD operations in a single controller.
Why Use a Generic Controller?
A generic controller helps:
- Minimize repetitive code.
- Make adding new models a breeze.
- Provide a consistent structure for your application.
Let’s dive into the implementation step by step!
Step 1: Setting Up the Controller
Start by creating a new controller:
php artisan make:controller GenericController
Step 2: Writing the Controller Logic
Here’s how you can design your GenericController to handle CRUD operations for any model:
namespace App\Http\Controllers; use Illuminate\Http\Request; use Illuminate\Support\Str; class GenericController extends Controller { protected function getModel($modelName) { $modelClass = 'App\Models\' . Str::studly($modelName); if (!class_exists($modelClass)) { abort(404, "Model $modelName not found."); } return new $modelClass; } public function index($model) { $modelInstance = $this->getModel($model); return response()->json($modelInstance::all()); } public function show($model, $id) { $modelInstance = $this->getModel($model); return response()->json($modelInstance::findOrFail($id)); } public function store(Request $request, $model) { $modelInstance = $this->getModel($model); $data = $request->validate($modelInstance->getFillable()); $created = $modelInstance::create($data); return response()->json($created, 201); } public function update(Request $request, $model, $id) { $modelInstance = $this->getModel($model); $item = $modelInstance::findOrFail($id); $data = $request->validate($modelInstance->getFillable()); $item->update($data); return response()->json($item); } public function destroy($model, $id) { $modelInstance = $this->getModel($model); $item = $modelInstance::findOrFail($id); $item->delete(); return response()->json(['message' => 'Deleted successfully.']); } }
Step 3: Dynamic Routing
Configure your routes to use dynamic endpoints:
use App\Http\Controllers\GenericController; Route::controller(GenericController::class)->prefix('api/{model}')->group(function () { Route::get('/', 'index'); Route::get('/{id}', 'show'); Route::post('/', 'store'); Route::put('/{id}', 'update'); Route::delete('/{id}', 'destroy'); });
Step 4: Prepare Your Models
Ensure each model has:
- A $fillable property to specify mass-assignable fields.
Example for a Post model:
namespace App\Models; use Illuminate\Database\Eloquent\Factories\HasFactory; use Illuminate\Database\Eloquent\Model; class Post extends Model { use HasFactory; protected $fillable = ['title', 'content']; }
Key Advantages
- Scalability: Easily handle new models by adding only the model file.
- Code Reusability: Reduces redundancy.
- Simplifies Maintenance: Focus on business logic without worrying about boilerplate code.
When to Use This Approach?
This is ideal for:
- Applications with standard CRUD logic.
- Projects where models share common behavior.
For more complex business logic, you may still need dedicated controllers.
The above is the detailed content of How to Build a Generic CRUD Controller in Laravel for Multiple Resources. For more information, please follow other related articles on the PHP Chinese website!

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