C# Conditional Compilation for Debug and Release Builds
In Visual Studio, when configuring the solution properties, you may encounter the need to distinguish between debug and release builds. This differentiation allows developers to define and use specific code paths, variable values, or compile-time constants based on the build configuration. One method to achieve this is through the use of conditional compilation directives.
To conditionally compile code based on the build configuration, you can use the #if, #elif, and #endif directives. However, there are certain considerations when using these directives to distinguish between debug and release builds.
In your specific case, you have defined both #define DEBUG and #define RELEASE preprocessor directives at the beginning of the file. However, you should note that Visual Studio already defines the DEBUG/_DEBUG preprocessor macro when in debug mode. Additionally, you should avoid checking for the RELEASE macro, as it is not typically defined.
To resolve this, you can remove the #define DEBUG directive and rely on the preprocessor definition set by Visual Studio for debugging. The correct way to conditionally execute code for debug or release builds is as follows:
#if DEBUG Console.WriteLine("Mode=Debug"); #else Console.WriteLine("Mode=Release"); #endif
By relying on the DEBUG preprocessor definition, you ensure that the correct code path is executed based on the current build configuration.
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