Home > Backend Development > C++ > How Can I Determine Design Mode from a Control's Constructor?

How Can I Determine Design Mode from a Control's Constructor?

Barbara Streisand
Release: 2025-01-10 12:25:41
Original
541 people have browsed it

How Can I Determine Design Mode from a Control's Constructor?

Detecting Design-Time vs. Run-Time within a Control Constructor

A common question involves identifying whether a control is in design mode or run-time mode from its constructor. While seemingly unusual, this is achievable.

The key lies in the LicenseManager.UsageMode property within the System.ComponentModel namespace. This property provides an enumeration that indicates the current application mode. The following code snippet effectively determines the mode:

<code class="language-csharp">bool isInDesignMode = (LicenseManager.UsageMode == LicenseUsageMode.Designtime);</code>
Copy after login

This concise method offers a reliable way to differentiate between design-time and run-time environments directly within a control's constructor.

The above is the detailed content of How Can I Determine Design Mode from a Control's Constructor?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template