Detailed explanation of the differences between Parameters.Add and Parameters.AddWithValue
TheParameters.Add
method allows you to specify parameter name, SqlDbType and value. The correct syntax is as follows:
<code class="language-csharp">command.Parameters.Add("@ID", SqlDbType.Int); command.Parameters["@ID"].Value = customerID;</code>
In contrast, Parameters.AddWithValue
has a more concise syntax and does not require specifying SqlDbType:
<code class="language-csharp">command.Parameters.AddWithValue("@demographics", demoXml);</code>
However, when using Parameters.AddWithValue
with the same syntax as Parameters.Add
, no compilation error occurs. Interestingly, the code also executes normally.
In-depth explanation
Internally, both methods use the same method:
<code class="language-csharp">return this.Add(new SqlParameter(parameterName, value));</code>
Parameters.AddWithValue
was introduced to replace Parameters.Add
to improve code clarity. In the overload of Parameters.Add
, the second argument is of type object, which can lead to confusion about which overload to use. This distinction is important because overloading has very different behavior.
Consider the following example:
<code class="language-csharp">SqlCommand command = new SqlCommand(); command.Parameters.Add("@name", 0);</code>
Although it looks like it calls the Add(string name, object value)
overload, it actually calls the Add(string name, SqlDbType type)
overload. This is because 0 is implicitly convertible to an enumeration type.
Therefore, using Parameters.AddWithValue
removes potential ambiguities and improves code readability. It is recommended to use Parameters.AddWithValue
in preference to get clearer and easier to maintain code.
The above is the detailed content of Parameters.Add vs. Parameters.AddWithValue: What's the Real Difference and Which Should I Use?. For more information, please follow other related articles on the PHP Chinese website!