How to Correctly Populate jqGrid Dropdowns Using jQuery $.post and ASP.NET MVC?

Using jQuery $.post and ASP.NET MVC to Populate jqGrid Dropdowns Correctly

This article addresses a common issue when dynamically populating jqGrid dropdowns using jQuery's $.post method and ASP.NET MVC: receiving an "undefined" value due to incorrect data formatting.

The Problem: Incorrect data format is sent to the jqGrid, resulting in "undefined" dropdown values. The jqGrid expects a specific format (e.g., value: "FE:FedEx; IN:InTime; TN:TNT"), but the request might be returning data in a different format.

The Original Request and Response: The original approach likely used $.post to fetch JSON data. However, the JSON structure didn't match jqGrid's expectations. The solution involved removing extra quotes during value creation and changing the controller's response to ContentResult(sb.ToString()). This is a less robust method.

A More Robust Solution: Leveraging dataUrl and buildSelect

A superior approach uses jqGrid's dataUrl and buildSelect features for cleaner, more maintainable code.

dataUrl: This property specifies a URL that returns data in a simpler format, suitable for parsing. The format doesn't need to be pre-formatted as a string of key-value pairs.

buildSelect: This callback function processes the server's response (ideally JSON) and constructs the correct dropdown HTML. This separates data retrieval from data formatting, improving code organization and readability.

Example Implementation:

Controller (ASP.NET MVC):

<code class="language-csharp">public JsonResult GetDestinationList() {
    List<string> allDestinations = GetAllDestinations();
    return Json(allDestinations, JsonRequestBehavior.AllowGet);
}</code>

jqGrid Configuration (JavaScript):

<code class="language-javascript">{
    name: 'destinations',
    editable: true,
    edittype: 'select',
    editoptions: {
        dataUrl: '/YourController/GetDestinationList', // Replace with your controller action
        buildSelect: function(data) {
            var s = '';
            if (data.length) {
                for (var i = 0; i < data.length; i++) {
                    var ri = data[i]; // Assuming data is an array of strings
                    s += '<option value="' + ri + '">' + ri + '</option>';
                }
            }
            return s;
        }
    }
}</code>

This revised approach provides a more efficient and maintainable solution for populating jqGrid dropdowns. The server returns simple data, and the client-side buildSelect function handles the formatting, leading to better separation of concerns. Remember to replace /YourController/GetDestinationList with the actual URL to your controller action.

The above is the detailed content of How to Correctly Populate jqGrid Dropdowns Using jQuery $.post and ASP.NET MVC?. For more information, please follow other related articles on the PHP Chinese website!