Use function to round T-SQL DateTime to nearest minute and hour
Question:
How to round a datetime column to the nearest minute and hour using existing functions?
Solution:
To round a datetime column to the nearest minute, use the following code:
<code class="language-sql">select dateadd(mi, datediff(mi, 0, @dt), 0)</code>
Where @dt is the datetime column you want to round.
To round a datetime column to the nearest hour, use the following code:
<code class="language-sql">select dateadd(hour, datediff(hour, 0, @dt), 0)</code>
For example, if your @dt column value is '09-22-2007 15:07:38.850', these queries will return:
Round up or down:
To round up or down, add half a minute or half an hour respectively, then truncate:
<code class="language-sql">-- 向上舍入到最近的分钟 select dateadd(mi, datediff(mi, 0, dateadd(s, 30, @dt)), 0) -- 向上舍入到最近的小时 select dateadd(hour, datediff(hour, 0, dateadd(mi, 30, @dt)), 0)</code>
These queries will return:
Truncate the time part to get the date:
Before SQL Server 2008 introduced the date data type, you could use a similar method to truncate the time portion from a datetime to get just the date:
<code class="language-sql">-- 获取 datetime 和固定点 (1900-01-01 00:00:00.000) 之间的日数 declare @days int set @days = datediff(day, 0, @dt) -- 将日数添加到固定点以获取日期,并将时间设置为 00:00:00.000 select dateadd(day, @days, 0)</code>
This will return the date portion of the @dt column with the time set to 00:00:00.000.
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