How to Generate Six Unique Random Lottery Numbers in C#?

C# lottery program: generate unique random numbers

Question:

How to write a program to generate six unique lottery numbers, ensuring that there are no duplicate numbers in a row?

Initial code snippet:

// 使用随机数对象生成6个随机数

int randomNumber1 = random.Next(1, 49);
int randomNumber2 = random.Next(1, 49);
int randomNumber3 = random.Next(1, 49);
int randomNumber4 = random.Next(1, 49);
int randomNumber5 = random.Next(1, 49);
int randomNumber6 = random.Next(1, 49);

textBox1.Text = randomNumber1.ToString();
textBox2.Text = randomNumber2.ToString();
textBox3.Text = randomNumber3.ToString();
textBox4.Text = randomNumber4.ToString();
textBox5.Text = randomNumber5.ToString();
textBox6.Text = randomNumber6.ToString();

Question:

The initial code snippet can generate random numbers, but there may be duplicate numbers in the same line.

Solution:

In order to generate unique random numbers, we need to store the generated numbers in a collection and check whether each new random number already exists. If duplicates are found, a new random number is generated until a unique number is found.

Alternatively, we can use a more efficient approach: generate a sequence of numbers between 1 and 49, shuffle it using the OrderBy and rnd.Next() methods, and then select from the shuffled sequence first six numbers.

var rnd = new Random();
var randomNumbers = Enumerable.Range(1, 49).OrderBy(x => rnd.Next()).Take(6).ToList();

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