Home > Database > Mysql Tutorial > How Do Aggregate Functions Work with the GROUP BY Clause in SQL?

How Do Aggregate Functions Work with the GROUP BY Clause in SQL?

DDD
Release: 2025-01-13 08:31:44
Original
730 people have browsed it

How Do Aggregate Functions Work with the GROUP BY Clause in SQL?

Understanding SQL's GROUP BY and Aggregate Functions

SQL's GROUP BY clause efficiently groups rows based on specified columns. However, confusion often arises when selecting columns not included in the grouping.

Consider this query:

<code class="language-sql">SELECT *
FROM order_details
GROUP BY order_no;</code>
Copy after login

This query will fail in many database systems (like Oracle) because it attempts to select all columns (*) while grouping by only order_no. This violates the rule that non-aggregated columns must be part of the GROUP BY clause.

The solution? Include non-aggregated columns in the GROUP BY clause alongside aggregate functions. For example:

<code class="language-sql">SELECT order_no, SUM(order_price)
FROM order_details
GROUP BY order_no;</code>
Copy after login

Here, order_no is in both the SELECT and GROUP BY clauses, while SUM(order_price) performs aggregation.

Addressing the key question:

Can aggregate functions access all columns within a group?

Yes, aggregate functions like SUM() operate across all rows within each group, calculating the aggregate value for the specified column. In the example above, SUM(order_price) totals the price for each order_no.

However, accessing non-aggregated columns without including them in the GROUP BY clause leads to errors. The database can't determine which value to select from multiple rows within a group.

Therefore, always include all non-aggregated columns in the GROUP BY clause, or restrict the SELECT clause to only aggregate functions when using GROUP BY.

The above is the detailed content of How Do Aggregate Functions Work with the GROUP BY Clause in SQL?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template