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How to Deserialize JSON Child Objects with Dynamic Key Names in C#?

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Release: 2025-01-13 19:12:44
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How to Deserialize JSON Child Objects with Dynamic Key Names in C#?

Deserialize child objects with dynamic key names

When dealing with JSON data that contains sub-objects with dynamic key names (usually numeric keys), it can be challenging to deserialize them using standard JSON.NET techniques.

To solve this problem, you can create a custom converter to handle dynamic key names and deserialize the values ​​into a typed container. The following custom converter TypedExtensionDataConverter<T> implements this functionality:

<code class="language-csharp">public class TypedExtensionDataConverter<T> : JsonConverter
{
    // ... (代码已省略)
}</code>
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This converter can then be used in the class structure to specify which property contains the sub-object with the dynamic key name:

<code class="language-csharp">[JsonConverter(typeof(TypedExtensionDataConverter<User>))]
class User
{
    // ... (代码已省略)
}</code>
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With this approach, sub-objects can be deserialized and stored in a typed container (in this case Dictionary<string, User>), providing a structured and easily accessible way to work with the data.

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