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How to Serialize Class Fields with System.Text.Json?

Barbara Streisand
Release: 2025-01-14 07:43:42
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How to Serialize Class Fields with System.Text.Json?

Using System.Text.Json.JsonSerializer and class fields

After upgrading to .NET Core 3, developers may encounter problems related to class fields and serialization. System.Text.Json.JsonSerializer requires properties for serialization and deserialization, but fields are often more convenient for representing class data. This begs the question: how to ensure that fields are handled correctly during serialization and deserialization.

In .NET Core 3.1, System.Text.Json does not serialize fields by default. As stated in the documentation, "Fields are not supported in System.Text.Json in .NET Core 3.1".

However, in later versions of .NET, there are some solutions available. In .NET 5 and above:

  • Public fields can be serialized by setting JsonSerializerOptions.IncludeFields to true.
  • You can also use the [JsonInclude] attribute to mark fields to be serialized.

To demonstrate this, consider a Car class containing the field Model and the property Year:

<code>public class Car
{
    public int Year { get; set; }
    public string Model;
}</code>
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In .NET Core 3.1, if IncludeFields is not set to true, the result of serializing Car looks like this:

<code>{"Year":2008}</code>
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Model field is ignored.

In .NET 5 and above, the following options are available to serialize Year properties and Model fields:

  1. Enable IncludeFields:
<code>var options = new JsonSerializerOptions { IncludeFields = true };
string json = JsonSerializer.Serialize(car, options);</code>
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  1. Use the [JsonInclude] attribute:
<code>[JsonInclude]
public string Model;
string json = JsonSerializer.Serialize(car);</code>
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By using these techniques, developers can ensure that their class fields are handled correctly during serialization and deserialization, consistent with class attributes.

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