How Can I Easily Generate Ordinal Numbers (1st, 2nd, 3rd, etc.) in C#?

Easily create ordinal numbers in C#

Creating ordinal numbers directly in C# (e.g., 1st, 2nd, 3rd) may not be directly supported by String.Format() or existing functions. However, there are some simple ways to achieve this.

One way is to use a custom function like this:

<code class="language-csharp">public static string AddOrdinal(int num)
{
    if (num <= 0) return num.ToString(); // 处理0和负数

    string number = num.ToString();
    if (num % 100 == 11 || num % 100 == 12 || num % 100 == 13)
    {
        return number + "th";
    }
    else
    {
        switch (num % 10)
        {
            case 1:
                return number + "st";
            case 2:
                return number + "nd";
            case 3:
                return number + "rd";
            default:
                return number + "th";
        }
    }
}</code>

This function receives an integer and checks its modulus to determine the appropriate ordinal suffix ("st", "nd", "rd", or "th"). For example:

<code class="language-csharp">Console.WriteLine(AddOrdinal(1));  // 输出：1st
Console.WriteLine(AddOrdinal(2));  // 输出：2nd
Console.WriteLine(AddOrdinal(3));  // 输出：3rd
Console.WriteLine(AddOrdinal(11)); // 输出：11th
Console.WriteLine(AddOrdinal(12)); // 输出：12th
Console.WriteLine(AddOrdinal(13)); // 输出：13th
Console.WriteLine(AddOrdinal(24)); // 输出：24th
Console.WriteLine(AddOrdinal(0));  // 输出：0
Console.WriteLine(AddOrdinal(-5)); // 输出：-5</code>

It should be noted that this code has not been internationalized and may need to be adjusted for other languages ​​where the ordinal format may be different. The improved code handles 0 and negative numbers, and handles numbers ending in 11, 12, 13 more accurately.

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