Safe assignment operator for JavaScript ?=
: Simplifying error handling in asynchronous operations
JavaScript introduces a new operator ?=
called the safe assignment operator. It aims to simplify error handling in your code, making it easier to read and maintain, especially when dealing with try-catch
error-catching functions.
?=
operator work?
When you use the ?=
operator, it checks whether the function or operation was successful. A result is returned on success; an error is returned on failure without causing the program to crash.
Here’s how it works:
<code class="language-javascript">const [error, result] ?= await fetch("https://dev.to/nddev_18/toan-tu-trong-java-script-1fl-temp-slug-9804469/edit");</code>
fetch
successfully obtains the data, error
will be null
and result
will be the data. fetch
fails, error
will contain the error details and result
will be null
. This example demonstrates its advantages:
try-catch
statements to call API. More specific API call error handling example:
<code class="language-javascript">async function getData() { const [fetchError, response] ?= await fetch("https://api.example.com/data"); if (fetchError) { console.error("Fetch error:", fetchError); return; } const [jsonError, jsonData] ?= await response.json(); if (jsonError) { console.error("JSON error:", jsonError); return; } return jsonData; }</code>
This is how you simplify error handling using the ?=
operator, which treats error handling as a subsequent step in code execution, making the code cleaner and easier to read.
Summary:
The safe assignment operator ?=
is a powerful tool for JavaScript developers, especially those who want to write code that is clear, reliable, and easy to maintain. By simplifying error handling, it helps prevent unexpected errors and makes code more robust. If you're dealing with Promises, async functions, or anything that might throw an error, try using the ?=
operator!
Thanks for reading and have a fulfilling day!
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