Value capture and reference capture in C# Lambda expressions
In C#, Lambda expressions can capture variables in an enclosing scope. By default, these captures are by reference, which means that the lambda expression accesses the same memory location as the original variable. However, in some cases you may want to capture a copy of a variable rather than a reference.
Question:
Consider the following C# code:
<code class="language-csharp">class Program { delegate void Action(); static void Main(string[] args) { List<Action> actions = new List<Action>(); for (int i = 0; i < 10; i++) actions.Add(() => Console.WriteLine(i)); foreach (Action a in actions) a(); } }</code>
Problem description:
The expected output is for each Lambda expression to print its corresponding i value while iterating through the list. However, in this example, all lambda expressions print the value 10, indicating that they all refer to the same variable i. This is because the lambda expression captures i by reference.
Solution:
To force the lambda expression to capture a copy of i , one solution is to first create a partial copy:
<code class="language-csharp">for (int i = 0; i < 10; i++) { int copy = i; // 创建局部副本 actions.Add(() => Console.WriteLine(copy)); }</code>
Explanation:
By creating a local copy of i in the loop, the Lambda expression captures the value of copy , which is a copy of the original i at that point in time. This ensures that each Lambda expression has its own copy of the value and the corresponding i value will be printed.
Difference:
The difference between capturing variables by reference and capturing them by value is how they interact with variables outside the lambda expression.
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