SQL Query for Retrieving Customer Data and Latest Purchases
Challenge:
Effectively retrieve customer details and their most recent purchase using a single SQL statement, given a customer table and a purchase table with a one-to-many relationship (one customer can have multiple purchases).
Approach:
The optimal solution involves a JOIN operation combined with a subquery to pinpoint the most recent purchase date for each customer. This ensures both accuracy and efficient query execution:
<code class="language-sql">SELECT c.*, p1.* FROM customer c JOIN purchase p1 ON (c.id = p1.customer_id) LEFT OUTER JOIN purchase p2 ON (c.id = p2.customer_id AND p1.date < p2.date) WHERE p2.date IS NULL;</code>
Performance Optimization:
Indexing: Creating a composite index on the purchase
table encompassing (customer_id, date, id)
columns significantly boosts performance. This allows the database to efficiently utilize a covering index during the outer join.
Data Normalization: While adding the last purchase details directly to the customer
table (denormalization) might seem faster for certain cases, it introduces redundancy and potential data integrity problems. Maintaining the normalized one-to-many structure and using efficient SQL queries remains the recommended approach.
LIMIT 1 (Caution): Using LIMIT 1
simplifies the query only if the purchase
table's id
column is inherently ordered by date. However, relying on LIMIT 1
without guaranteed ordering can lead to inaccurate results if data insertion isn't consistently ordered by date or another relevant column. The provided solution is more robust and handles various data ordering scenarios.
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