A way to ensure that integer division always rounds up
This article aims to find a reliable way to ensure that integer division always rounds up.
Reviewing the original method
The original suggestion was to convert the integer to a double precision floating point number and round the result up using the Math.Ceiling()
function. While this approach appears to work, type conversions can introduce unnecessary complexity and potential precision issues.
A robust solution
To solve this problem, a more comprehensive and robust solution is provided below:
<code class="language-java">public static int DivRoundUp(int dividend, int divisor) { if (divisor == 0 || (dividend == Integer.MIN_VALUE && divisor == -1)) throw new ArithmeticException("Invalid input"); // 显式处理异常情况 int roundedTowardsZeroQuotient = dividend / divisor; boolean dividedEvenly = (dividend % divisor) == 0; if (dividedEvenly) return roundedTowardsZeroQuotient; boolean wasRoundedDown = ((divisor > 0) == (dividend > 0)); if (wasRoundedDown) return roundedTowardsZeroQuotient + 1; else return roundedTowardsZeroQuotient; }</code>
Explanation
This function handles all possible situations meticulously, including:
Key Considerations
By following these principles, we can develop robust and reliable rounding-up code for integer division.
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