Home > Backend Development > C++ > How to Determine if a Point Lies to the Left or Right of a Line?

How to Determine if a Point Lies to the Left or Right of a Line?

Mary-Kate Olsen
Release: 2025-01-21 05:19:16
Original
188 people have browsed it

How to Determine if a Point Lies to the Left or Right of a Line?

Determine the position of the point relative to the line

In order to separate a set of points into two different sets based on their position relative to the line, you need to determine whether a point is to the left or right of the line. Here's one way to accomplish this:

The cross product of two vectors provides the orientation of a point relative to a line. Given a straight line defined by two points a and b and a point c, the cross product formula is:

<code>(b.x - a.x)*(c.y - a.y) - (b.y - a.y)*(c.x - a.x)</code>
Copy after login

If the result is positive, it means that point c is to the left of line a-b. Conversely, if the result is negative, then c is to the right of the line. If the result is 0, then c is collinear with the line (that is, it lies on the line).

Example implementation

This is a Python code implementation using the cross product method:

<code class="language-python">def isLeft(a, b, c):
  return (b.x - a.x)*(c.y - a.y) - (b.y - a.y)*(c.x - a.x) > 0</code>
Copy after login

Where a, b and c represent three points.

Other notes

If the line is horizontal, you can adjust the cross product formula to determine whether the point is above or below the line:

<code>(b.x - a.x)*(c.y - a.y) - (b.y - a.y)*(c.x - a.x) > 0  (上方)</code>
Copy after login

This method provides a simple and efficient way to determine the position of a point relative to a line, allowing points to be divided into two sets based on their position on either side of the line.

The above is the detailed content of How to Determine if a Point Lies to the Left or Right of a Line?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template