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How to Deserialize Derived Types Efficiently with Json.Net?

Patricia Arquette
Release: 2025-01-21 18:38:09
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How to Deserialize Derived Types Efficiently with Json.Net?

Json.Net derived type deserialization techniques

Json.Net is a powerful JSON serialization and deserialization tool, but when dealing with derived types, deserialization becomes more complicated. This article explores how to efficiently use Json.Net to deserialize derived types.

Type name processing

Successful deserialization of derived types requires type name handling to be enabled. This setting instructs Json.Net to include type names in the serialized JSON stream. By default, type name handling is disabled, which can lead to ambiguous deserialization results when dealing with derived types.

Enable type name handling

To enable type name handling, you can specify JsonSerializerSettings in a TypeNameHandling.All object. An example is as follows:

<code class="language-csharp">JsonSerializerSettings settings = new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.All };</code>
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Serialization and Deserialization

With type name handling enabled, derived types can be serialized and deserialized as follows:

<code class="language-csharp">// 序列化
string Serialized = JsonConvert.SerializeObject(inheritanceList, settings);

// 反序列化
List<BaseClass> deserializedList = JsonConvert.DeserializeObject<List<BaseClass>>(Serialized, settings);</code>
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Important Notes

Enabling type name handling can cause some problems:

  • Data size increased: The serialized JSON stream will be larger because it now contains the type name.
  • Performance impact: Deserialization may be slower because it involves comparing the type name to available registered types.

Summary

By enabling type name handling in Json.Net, derived types can be efficiently deserialized and their inheritance hierarchy preserved. This feature allows you to handle complex data structures in a convenient and reliable way.

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