What's the Constructor Execution Order in C# and How Does it Differ from Java?

Detailed explanation of C# constructor execution order

When using constructors in C#, it is crucial to understand their order of execution. The constructor of the most derived class is executed first, and then the constructor of its base class is executed in order of inheritance.

Please see the following code example:

<code class="language-c#">public class DerivedClass : BaseClass {
    public DerivedClass(int param1, int param2) : base(param1) {
        // 派生类构造函数逻辑
    }
}</code>

In this case, the execution sequence is as follows:

1. Member variable initialization: The member variables of DerivedClass and BaseClass are initialized to default values.
2. Variable initializer execution: The variable initializer of DerivedClass is executed.
3. Constructor chain call: Call the base class constructorBaseClass(param1).
4. Base class constructor execution: BaseClass(param1) is executed.
5. Derived class constructor body execution : The constructor body of DerivedClass is executed.

It should be noted that this execution order is different from Java. In Java, base classes are initialized before variable initializers are executed. Understanding this difference is critical for porting code between the two languages.

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