How to Deserialize JSON Data in C# using Newtonsoft.Json?

Use Newtonsoft.Json to deserialize JSON data in C#

Newtonsoft.Json library provides efficient JSON data deserialization function. The JsonConvert.DeserializeObject method allows you to convert JSON data into C# objects for flexible data processing.

Code example:

<code class="language-csharp">// 将JSON数据反序列化为字符串列表
List<string> list = JsonConvert.DeserializeObject<List<string>>(reader.Read().ToString());

// 将JSON数据反序列化为自定义Album对象
var album = JsonConvert.DeserializeObject<Album>(jObject["albums"][0].ToString());</code>

LINQ to JSON alternative

Newtonsoft.Json also provides LINQ to JSON functionality, allowing programmatic traversal and query of JSON data. Easily extract specific values ​​or manipulate data without manual parsing.

Code example:

<code class="language-csharp">// 将JSON数据解析为JObject
JObject jObject = JObject.Parse(reader.ReadLine());

// 使用LINQ选择特定数据
var coverImageUrl = (string)jObject["albums"][0]["cover_image_url"];</code>

Use dynamic types

To simplify the deserialization process, you can use dynamic typing. This allows dynamic access to properties without the need for strongly typed classes.

Code example:

<code class="language-csharp">// 将JSON数据反序列化为动态对象
dynamic results = JsonConvert.DeserializeObject<dynamic>(json);

// 动态访问属性
var id = results.Id;
var name = results.Name;</code>

Other notes:

• Use using statements for efficient resource management.
• Specify the correct deserialization type to ensure correct type conversion.
• Use LINQ to JSON to manipulate data more flexibly.
• Using dynamic types simplifies the deserialization process and improves ease of use.

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