How to Deserialize JSON in .NET using Newtonsoft or LINQ to JSON?

Use Newtonsoft or LINQ to JSON to deserialize JSON in .NET

Question:

How to convert JSON data into usable .NET objects using Newtonsoft or LINQ to JSON?

Answer:

Use Newtonsoft.Json:

1. Add the Newtonsoft.Json NuGet package to your project.
2. Use Newtonsoft.Json.JsonConvert.DeserializeObject to deserialize JSON data into strongly typed objects.
3. Access the properties of the deserialized object.

Use LINQ to JSON:

1. Use Newtonsoft.Json.Linq.JObject.Parse to parse JSON data into JObject.
2. Use LINQ queries to navigate and extract data from JObjects.

Use C# dynamic typing:

1. Use Newtonsoft.Json.JsonConvert.DeserializeObject to deserialize JSON data into dynamic objects.
2. Access the properties of dynamic objects directly without specifying the type.

Sample code using dynamic typing:

<code class="language-csharp">public class Example
{
    public int Id { get; set; }
    public string Name { get; set; }
}

// JSON字符串
string json = "{\"Id\": 1, \"Name\": \"biofractal\"}";

// 反序列化为动态对象
dynamic results = JsonConvert.DeserializeObject<dynamic>(json);

// 访问属性
int id = results.Id;
string name = results.Name;

// 如需创建强类型对象
Example example = new Example
{
    Id = id,
    Name = name,
};</code>

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