How Can I Get a Double Result When Dividing Integers in Programming?

How to obtain dual -precision floating -point results through integer removal?

In most programming languages, the two integers will perform an integer division by default, and the result is also an integer. However, in some cases, you may need dual -precision floating -point results. This requires a modification method to convert the number of operations into dual -precision floating points before performing division.

Solution:

A simple solution is to convert both integer into dual -precision floating -point numbers before performing division. This ensures that the division of operations treat the number of operations as dual -precision floating points, so as to obtain dual -precision quotient. The following code fragment demonstrates this:

Optimization:

double num3 = (double)num1/(double)num2;

In C#, if any parameter in the method is divided into a dual -precision floating point number, the language will automatically use the dual -precision floating point number to remove the method to obtain the double -precision floating point output. Therefore, it is also effective to convert only one of the operations to dual -precision floating points:

When one of the operations is already a dual -precision floating point number, this optimization can improve the readability and efficiency of the code.

<多> More resources:

double num3 = (double)num1/num2;

For more information about the dual -precision floating point division in programming, please refer to the following resources:

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