How Do I Get a Double Result When Dividing Integers in C#?

Achieving Double-Precision Integer Division in C#

Standard integer division in C# truncates the result, discarding any fractional part. To obtain a double-precision floating-point result from integer division, you need to explicitly convert (cast) at least one of the integers to a double before the division.

Casting Method:

The most straightforward method is to cast both integers to double:

<code class="language-csharp">double num3 = (double)num1 / (double)num2;</code>

This forces the division to be performed using floating-point arithmetic, resulting in a double value that preserves the fractional component.

Simplified Casting:

You can achieve the same result by casting only one of the integers:

<code class="language-csharp">double num3 = (double)num1 / num2; </code>

Since one operand is a double, C# automatically promotes the other integer to a double before performing the division. This is generally preferred for its conciseness.

Further Reading:

For a more comprehensive understanding of floating-point arithmetic and related concepts in C#, explore resources like Dot Net Perls: https://www.php.cn/link/91109a77036a730296d6305a9794fa13

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