How to Deserialize JSON Objects with Non-Default Constructors in JSON.net?

JSON objects with non -default constructors in json.net in json.net

JSON.NET uses the default constructor to use the default constructor when the derivative object is. However, if you have a class with a default constructor and non -default constructor, you may encounter problems when trying to use non -default constructor functions for reference.

Use [JSONCONSTRUCTOR] Features:

To indicate that JSON.NET uses a non -default constructor, you can add the [JSONCONSTRUCTOR] feature. This characteristic must be placed on a constructor to be used for deepericularization.

Example:

Make sure the constructor parameter name matches the corresponding JSON attribute name (ignore the lower case).

Jsonconveter:

<code class="language-csharp">[JsonConstructor]
public Result(int? code, string format, Dictionary<string, string> details = null)
{
    // 构造函数逻辑
}</code>

If you cannot modify the class or do not want to use the characteristics, you can create a custom JSONCONVERRER to manually process the derivative.

Example:

Finally, add the converter to the serialization program settings before the deepertdialization:

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