Why Does My Random Number Generator Only Produce One Number, and How Can I Fix It?

The random number generator generates only one random number problem and solution

This article discusses a random number generator function

Only one random number is generated. The root cause of the problem is that the function creates a new

instance at each call. Since the internal state of the instance is based on the system clock initialization, in a close cycle, multiple calls will get the same value. RandomNumber Random In order to solve this problem and ensure the accuracy of random numbers, a Random instance should be created and reused. The following code shows how to achieve:

Random By using the statement, we synchronize the visits of

instances to ensure that each time

<code class="language-csharp">private static readonly Random random = new Random();
private static readonly object syncLock = new object();

public static int RandomNumber(int min, int max)
{
    lock (syncLock)
    {
        return random.Next(min, max);
    }
}</code>

will generate a unique random number in the same line.

lock Another method is to use Random variables to maintain a RandomNumber instance for each thread to avoid synchronization:

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