JavaScript deconstruction and assignment: simplify code and improve readability
JavaScript's deconstructed assignment allows you to extract individual elements from an array or object using concise syntax and assign them to variables, simplifying the code and making it clearer and easier to read.
Deconstruction and assignment are widely used, including processing API responses, functional programming, and in frameworks and libraries such as React. It can also be used for nested objects and arrays, default function parameters, variable value exchange, return multiple values from a function, for-of loops, and regular expression processing.
When using deconstructed assignments, you need to pay attention to the following points: You cannot start a statement with curly braces, because it looks like a block of code. To avoid errors, either declare the variable or use brackets if the variable is declared. Also be careful to avoid mixing declared and undeclared variables.
How to use deconstruction assignment
Deconstructing array
Suppose we have an array:
const myArray = ['a', 'b', 'c'];
Deconstruction provides an easier and less error-prone alternative to extracting each element:
const [one, two, three] = myArray; // one = 'a', two = 'b', three = 'c'
You can ignore certain values by omitting the value name when assigning, for example:
const [one, , three] = myArray; // one = 'a', three = 'c'
Or use the rest operator (...) to extract the remaining elements:
const [one, ...two] = myArray; // one = 'a', two = ['b', 'c']
Deconstructing object
Deconstruction also applies to objects:
const myObject = { one: 'a', two: 'b', three: 'c' }; // ES6 解构示例 const {one, two, three} = myObject; // one = 'a', two = 'b', three = 'c'
In this example, the variable names one, two, and three match the object property name. We can also assign attributes to variables of any name, for example:
const myObject = { one: 'a', two: 'b', three: 'c' }; // ES6 解构示例 const {one: first, two: second, three: third} = myObject; // first = 'a', second = 'b', third = 'c'
Deconstruct nested objects
More complex nested objects can also be referenced, for example:
const meta = { title: 'Destructuring Assignment', authors: [ { firstname: 'Craig', lastname: 'Buckler' } ], publisher: { name: 'SitePoint', url: 'https://www.sitepoint.com/' } }; const { title: doc, authors: [{ firstname: name }], publisher: { url: web } } = meta; /* doc = 'Destructuring Assignment' name = 'Craig' web = 'https://www.sitepoint.com/' */
This seems a bit complicated, but remember that in all deconstructed assignments:
Precautions
There are some other things to note. First, you can't start the statement with curly braces, because it looks like a code block, for example:
// 这会失败 { a, b, c } = myObject;
You have to declare variables, for example:
// 这可以工作 const { a, b, c } = myObject;
Or use brackets if the variable has been declared, for example:
// 这可以工作 ({ a, b, c } = myObject);
You should also be careful to avoid mixing declared and undeclared variables, such as:
// 这会失败 let a; let { a, b, c } = myObject; // 这可以工作 let a, b, c; ({ a, b, c } = myObject);
The above are the basic knowledge of deconstruction. So, under what circumstances does it work? I'm glad you asked this question.
Deconstructed use cases
Simpler statement
Variables can be declared without explicitly defining each value, for example:
// ES5 var a = 'one', b = 'two', c = 'three'; // ES6 const [a, b, c] = ['one', 'two', 'three'];
Authentic, the deconstructed version is longer. It's easier to read, although it may not be the case for more items.
Variable value exchange
Swap values require a temporary third variable, but using deconstruction is much easier:
var a = 1, b = 2; // 交换 let temp = a; a = b; b = temp; // a = 2, b = 1 // 使用解构赋值交换 [a, b] = [b, a]; // a = 1, b = 2
You are not limited to two variables; you can rearrange any number of items, such as:
const myArray = ['a', 'b', 'c'];
Default function parameters
Suppose we have a prettyPrint() function to output our meta object:
const [one, two, three] = myArray; // one = 'a', two = 'b', three = 'c'
If there is no deconstruction, you need to parse this object to ensure that appropriate default values are available, for example:
const [one, , three] = myArray; // one = 'a', three = 'c'
Now, we can assign default values to any parameter, for example:
const [one, ...two] = myArray; // one = 'a', two = ['b', 'c']
But we can use deconstruction to extract values and assign default values if necessary:
const myObject = { one: 'a', two: 'b', three: 'c' }; // ES6 解构示例 const {one, two, three} = myObject; // one = 'a', two = 'b', three = 'c'
I'm not sure if this is easier to read, but it's obviously shorter.
Return multiple values from function
Thefunction can only return one value, but this can be a complex object or a multidimensional array. Deconstructing assignment makes this more practical, for example:
const myObject = { one: 'a', two: 'b', three: 'c' }; // ES6 解构示例 const {one: first, two: second, three: third} = myObject; // first = 'a', second = 'b', third = 'c'
for-of loop
Consider an array of book information:
const meta = { title: 'Destructuring Assignment', authors: [ { firstname: 'Craig', lastname: 'Buckler' } ], publisher: { name: 'SitePoint', url: 'https://www.sitepoint.com/' } }; const { title: doc, authors: [{ firstname: name }], publisher: { url: web } } = meta; /* doc = 'Destructuring Assignment' name = 'Craig' web = 'https://www.sitepoint.com/' */
ES6's for-of is similar to for-in, except that it extracts each value instead of index/key, for example:
// 这会失败 { a, b, c } = myObject;
Deconstruction assignment provides further enhancements, such as:
// 这可以工作 const { a, b, c } = myObject;
regular expression processing
Regular expression functions (such as match) return an array of matches, which can constitute the source of deconstructed assignments:
// 这可以工作 ({ a, b, c } = myObject);
Further reading
Frequently Asked Questions about ES6 Deconstruction Assignment (FAQ)
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