jQuery Array Search Simple Example

This concise example demonstrates how jQuery's $.map() function efficiently retrieves values from an array of JavaScript objects. The array contains day-price pairs; the goal is to find the price associated with a specific day.

var dayArr = [
  { "day": "day01", "price": "0" },
  { "day": "day02", "price": "0" },
  { "day": "day03", "price": "0" }
];

var findDay = 'day02'; // Target day

var price = $.map(dayArr, function(value, key) {
  if (value.day == findDay) {
    return value.price;
  }
});

console.log(price); // Output: 0

jQuery Array Search: Frequently Asked Questions

This section addresses common questions regarding jQuery's array search capabilities.

Q: How does jQuery.inArray() function?

A: jQuery.inArray() searches for a specific value within an array. If found, it returns the value's index; otherwise, it returns -1. It uses strict equality (===), requiring both value and type to match.

Q: jQuery.inArray() vs. JavaScript's indexOf()?

A: Both locate values in arrays. jQuery.inArray() supports array-like objects, while indexOf() only works with arrays. jQuery.inArray() offers an optional starting index parameter, unlike indexOf().

Q: Checking Value Existence with jQuery.inArray()?

A: Use this pattern:

var array = [1, 2, 3, 4, 5];
var value = 3;
if ($.inArray(value, array) !== -1) {
  alert(value + " exists in the array");
} else {
  alert(value + " does not exist in the array");
}

Q: jQuery.inArray() and Multidimensional Arrays?

A: jQuery.inArray() doesn't directly handle multidimensional arrays. Nested loops are necessary to search within each sub-array.

Q: Finding a Value's Index with jQuery.inArray()?

A:

var array = [1, 2, 3, 4, 5];
var value = 3;
var index = $.inArray(value, array);
if (index !== -1) {
  alert("The index of " + value + " is " + index);
} else {
  alert(value + " is not in the array");
}

Q: jQuery.inArray() with Objects?

A: jQuery.inArray() is unsuitable for objects. Alternative methods, like iterating through object properties, are required.

Q: Removing a Value with jQuery.inArray()?

A:

var array = [1, 2, 3, 4, 5];
var value = 3;
var index = $.inArray(value, array);
if (index !== -1) {
  array.splice(index, 1);
}

Q: jQuery.inArray() with Strings?

A: Works identically to numbers.

Q: Finding All Occurrences with jQuery.inArray()?

A: jQuery.inArray() only finds the first occurrence. Looping and repeated calls are needed for all instances.

Q: jQuery.inArray() with Arrays of Objects?

A: Direct use is impossible. Iterate through the array and compare object properties individually.

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