Why does my RxJS code not take effect when operating on streams?
Frequently Asked Questions and Solutions for Invalid RxJS Streaming Operation
When using RxJS to process data flows, developers often encounter situations where operators cannot work as expected. This article will analyze a typical case, explain the root cause of the problem and provide solutions.
Problem: The operation of even multiplying by two fails
Suppose we need to process an array of numbers, filter out even numbers and multiply them by 2. The code using of
operator, filter
and map
operator is as follows:
import { of } from 'rxjs'; import { map, filter } from 'rxjs/operators'; const source$ = of([1, 2, 3, 4, 5]); source$.pipe( filter(item => item % 2 === 0), map(num => num * 2) ).subscribe(value => console.log(value));
The expected outputs are 4
and 8
, but the actual result does not have any output.
Cause analysis
The problem lies in the usage of the of
operator. of
operator emits the input parameters as a whole, rather than transmitting each element in the array separately. Therefore, item
received by filter
and map
operators is the entire array [1, 2, 3, 4, 5]
, rather than a single number in the array. The judgment of item % 2 === 0
is invalid for the entire array, causing filter
to filter out all content.
Solution: Use the from
operator
To solve this problem, from
operator should be used instead of the of
operator. from
operator splits the array into individual elements and emits it into the Observable one by one. The modified code is as follows:
import { from } from 'rxjs'; import { map, filter } from 'rxjs/operators'; const source$ = from([1, 2, 3, 4, 5]); source$.pipe( filter(item => item % 2 === 0), map(num => num * 2) ).subscribe(value => console.log(value));
Now filter
and map
operators will handle each number correctly, with the final outputs 4
and 8
. This demonstrates the importance of choosing the correct RxJS operator for correct processing of data flows.
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