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PHP读取某站点的链接

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Release: 2016-06-13 10:22:10
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原理:读取某站点的源文件,再利用正则分析其源代码,得到所有链接

/**********qiushuiwuhen(2002-5-20)***********/
if(empty($url))$url = "http://www.csdn.net/expert/";//设置url
$site=substr($url,0,strpos($url,"/",8));//站点
$base=substr($url,0,strrpos($url,"/")+1);//文件所在目录
$fp = fopen($url, "r" );//打开url
while(!feof($fp))$contents.=fread($fp,1024);//
$pattern="|href=["]?([^ "]+)[" ]|U";
preg_match_all($pattern,$contents, $regArr, PREG_SET_ORDER);//匹配所有href=
for($i=0;$iif(!eregi("://",$regArr[$i][1]))//是否是相对路径,即是否还有://
if(substr($regArr[$i][1],0,1)=="/")//是否是站点的根目录
echo "link".($i+1).":".$site.$regArr[$i][1]."
";//根目录
else
echo "link".($i+1).":".$base.$regArr[$i][1]."
";//当前目录
else
echo "link".($i+1).":".$regArr[$i][1]."
";//相对路径
}
fclose($fp);
?>

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