Home Backend Development PHP Tutorial 上传文件名称中文失败,该怎么处理

上传文件名称中文失败,该怎么处理

Jun 13, 2016 am 10:22 AM
files name quot

上传文件名称中文失败
$dir = $_SERVER['DOCUMENT_ROOT']."/uploads/";
  //上传的文件重命名
$filename = $_FILES[$myfile]['name'];
//$filename = mb_convert_encoding($_FILES[$myfile]['name'],"UTF-8","GBK");
//$filename = iconv("gb2312","UTF-8",$_FILES[$myfile]['name']);
//echo $filename;die;
//上传文件的函数move_uploaded_file(文件临时的目录,文件加载的目录)
if(move_uploaded_file($_FILES[$myfile]['tmp_name'],$dir.$filename)){
//解压上传文件
  dp_unzipfile($filename,$path);
//echo "文件上传成功";
}else{
echo "上传文件失败";
}

------解决方案--------------------

PHP code
windows下的路径要这样:D:\\WebService\\doc.juren9.com\\uploads\\房间阿斯顿.zipLinux:# /WebService/doc.juren9.com/uploads/房间阿斯顿.zip.gz<br><font color="#e78608">------解决方案--------------------</font><br>
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$dir = $_SERVER['DOCUMENT_ROOT']."/uploads/";
//上传的文件重命名
$filename = $_FILES[$myfile]['name'];
//$filename = mb_convert_encoding($_FILES[$myfile]['name'],"UTF-8","GBK");
//$filename……

------解决方案--------------------
中文可以的,把$_FILES[$myfile]打印出来看看
------解决方案--------------------
这是我正在做的项目里的上传图片的文件,伱拿去用吧!!
PHP code
/*** 功能:*   上传图片* 参数说明:*   $imgpath:    FILE变量* 返回值:*   1:$imgpath   上传图片成功后的完整图片路径*   2:false      上传图片失败*   2:false      上传图片失败失败* 版本:*   v1.0 07年8月5日作第1次修改,*/  function upload_image($imgpath){           $name=$imgpath["name"];    $tmp_name=$imgpath["tmp_name"];    $type=$imgpath["type"];    $size=$imgpath["size"];    $uploadfile = "../index/upload_image/".$imgpath['name'];   //time()."_".   上传的位置           $maxsize=500*1024;                                           //最大允许上许文件大小    if($name==""){                                             //文件名为空         echo"<script>alert('请先选择要上传的图片文件!');          window.history.back();</script>";    }        if($size>$maxsize){                                       //超过规定大小             echo"<script>alert('上传文件大小不能超过500K! ');window.history.back();</script>";        exit;    }         if(move_uploaded_file($tmp_name,$uploadfile))         return $uploadfile;    else if (copy($tmp_name,$uploadfile))        return $uploadfile;    else        return false;    }//upload_image函数部分 在伱需要上传图片的页面调用这个函数 //如果不是一个页面 别忘记在那个页面包含这个文件    $photo=$_FILES['photo'];  upload_image($photo);?><br><font color="#e78608">------解决方案--------------------</font><br>重复名  就行  吧<div class="clear">
                 
              
              
        
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