AJAX传递参数,PHP无法获取解决思路

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Release: 2016-06-13 10:23:23
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AJAX传递参数,PHP无法获取
AJAX代码如下:

JScript code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->type:'POST',url:'../php/a.php?ID='+'abc',success: function(data){    alert(data);}
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PHP代码如下:
PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->echo $_GET['ID'];
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为什么js文件能弹出显示‘abc'的对话框,PHP页面却什么也没有呢?

------解决方案--------------------
什么“什么也没有”? 你怎么访问的。url上带ID了吗?
------解决方案--------------------
不可能。既然ajax都能获取到。说明php返回了值。/a.php?ID=33 是这样访问的吗?
------解决方案--------------------

ajax.html
HTML code
            <meta charset="gb2312">        <title></title>            <script src="http://code.jquery.com/jquery-latest.js"></script>        <style>                </style>                        <script>            $.ajax({                type:'POST',                url:'index.php?ID='+'abc',                success: function(data)                {                    alert(data);                }            })        </script>    <br><font color="#e78608">------瑙e</font>
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