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mysql数据库中2个表建立关系解决思路

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Release: 2016-06-13 10:25:23
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mysql数据库中2个表建立关系
表1 page:(page_id,page_text,img_exist)=>(页面id,页面内容,是否存在图片1存在,0不存在)
表2 image:(img_id,img_name)=>(图片id,图片名)  
现在表2增加1列: image:(img_id,img_name,page_id)
现在要求是 把页面中含有的图片全部归类到属于哪一个页面id。

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php $DBserver         = "localhost";$DBname           = "new";$DBuser           = "root";$DBpassword       = "";$con = mysql_connect("localhost","root","");mysql_select_db("new");$query = mysql_query("select page_id,page_text from pagecontents where img_exist > 0") or die(mysql_error() );while($rows = mysql_fetch_array($query)){    $pid = $rows['page_id'];    $ptext = $rows['page_text'];    $ptext = mysql_real_escape_string($ptext);    $ptext = preg_replace('/poweredby_mediawiki_88x31\.png/s','',$ptext); if(preg_match_all('/.+\.(gif|swf|jpg|png)/is',$ptext,$match)){    $ptext = $match[1][0];    $ptext = mysql_real_escape_string($ptext);}    mysql_select_db("lookdb",$con);    $sql = "update imgmulu set page_id = ('{$pid}')  where img_name = ('{$ptext}')";    mysql_query($sql) or die(mysql_error()); }?>
Copy after login


这样运行没效果,求高手指教下,谢谢帮助。



------解决方案--------------------
preg_replace('/[\r\n]+/s','',$s);
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