一个网页的图片名的截取,该怎么处理

一个网页的图片名的截取
网页的代码里很多：

HTML code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><a href="/index.php/Image:EISL_1.1.6.gif" class="image" title="Image:EISL 1.1.6.gif"><img src="/images/0/04/EISL_1.1.6.gif" alt="Image:EISL 1.1.6.gif"    style="max-width:90%"  style="max-width:90%" longdesc="/index.php/Image:EISL_1.1.6.gif"></a><br>铺砌搅拌的均质池<br><a href="/index.php/Image:EISL_1.1.7.gif" class="image" title="Image:EISL 1.1.7.gif"><img src="/images/d/da/EISL_1.1.7.gif" alt="Image:EISL 1.1.7.gif"    style="max-width:90%"  style="max-width:90%" longdesc="/index.php/Image:EISL_1.1.7.gif"></a><br>穿孔导流槽式均质池<br><a href="/index.php/Image:EISL_1.1.8.gif" class="image" title="Image:EISL 1.1.8.gif"><img src="/images/e/e9/EISL_1.1.8.gif" alt="Image:EISL 1.1.8.gif"    style="max-width:90%"  style="max-width:90%" longdesc="/index.php/Image:EISL_1.1.8.gif"></a>

我现在只需要得到图片名(EISL 1.1.6.gif),该怎么做呢？
用正则截取还是别的什么办法呢？求指导


------解决方案--------------------
$contents = preg_replace('/poweredby_mediawiki_88x31\.png/s','',$contents); //加一步，过滤掉它。