PHP socket 发到指定的地址,该如何解决

PHP socket 发到指定的地址
有3个用户通过socket登录到了服务端，通过mysql记录下了三个用户的IP与端口分别为：
A: 192.168.1.100:13564 B:192.168.1.100:13565 C：192.168.1.100:13566

现在我想在客户A发一个指今（包含客户B的端口），服务端接受分析后从数据库取出客户B对应的地址发个TEST字符给B

我在服务端加入如下代码，出现错误，
PHP Warning: socket_connect(): unable to connect [0]: 提供了一个无效的参数。

PHP code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->$conn = socket_connect ($socket, '192.168.1.100', 13565);  $buffer = "ok";$command = socket_sendto($socket,$buffer,strlen($buffer),0,'192.168.1.100','192.168.1.100');

可以在服务端用socket_sendto吗？这个怎么实现啊？


 
服务端：

PHP code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->$addr = "192.168.1.121";$port = 1338;$remoteIP = "";$remotePort = "";$socket = socket_create(AF_INET,SOCK_STREAM,SOL_TCP);if($socket 

客户端：

PHP code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->// Client   // 设置错误处理  error_reporting (E_ALL);  // 设置处理时间  set_time_limit (0);    $ip = "192.168.1.121";       // IP 地址  $port = 1338;            // 端口号    $socket = socket_create (AF_INET, SOCK_STREAM, SOL_TCP);   // 创建一个SOCKET  if ($socket)      echo "socket_create() successed!\n";  else      echo "socket_create() failed:".socket_strerror ($socket)."\n";    $conn = socket_connect ($socket, $ip, $port);       // 建立SOCKET的连接  if ($conn)      echo "Success to connection![".$ip.":".$port."]\n";  else      echo "socket_connect() failed:".socket_strerror ($conn)."\n";    echo socket_read ($socket, 1024);       $stdin = fopen ('php://stdin', 'r');  while (true)  {      $command = trim (fgets ($stdin, 1024));      socket_write ($socket, $command, strlen ($command));      $msg = trim (socket_read ($socket, 1024));      echo $msg."\n";      if ($msg == "Bye-Bye")          break;  }  fclose ($stdin);  socket_close ($socket);<div class="clear">
                 
              
              
        
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