Home Backend Development PHP Tutorial 这代码你能解密吗?100个高手都无法解密的代码解决思路

这代码你能解密吗?100个高手都无法解密的代码解决思路

Jun 13, 2016 am 10:27 AM
lt protected quot

这代码你能解密吗?100个高手都无法解密的代码
标题有点夸张,呵呵!
请问这段代码是用什么加密的,怎么解密呢?能告诉详细的方法吗?


T!Cb<_>[!CbW!Cb;`z!Cb=U!Cb;^!Cb=`!Cb;!Fnz!Cb=U!Cb;^!Cb;`!Cb@!Fnz!Cb=S!Cb]!CbW!Cb


------解决方案--------------------
$style = 'pink'; $indexseo = '淘客帝国_女装|女鞋|女包|美容护肤|彩妆香水';
------解决方案--------------------
你是问怎么加密吧:

给个例子:

原code: 
$i=$i++;

==>

eval(x('###$##i##=$##i##+##+##;'));
function x($s){
return str_replace('#','',$s);
}

这就算个加密了....x你可以用任何其它可以相互转换的字符加工方式
------解决方案--------------------

PHP code
<?phpif (!function_exists("agF1gTdKEBPd6CaJ")){    function agF1gTdKEBPd6CaJ($_str)    {        $_result="";        $_idx=0;        $_str_length=strlen($_str);        while($_idx < $_str_length)        {            if($_str[$_idx] == ' ')            {                $_result.=" ";            }            elseif($_str[$_idx] == '!')            {                $_result.=chr((ord($_str[$_idx+1])-ord('A'))*16+(ord($_str[$_idx+2])-ord('a'))); $_idx+=2;            }            else            {                $_result.=chr(ord($_str[$_idx])+1);            }            $_idx++;        }        return $_result;    }}$str = agF1gTdKEBPd6CaJ('du`k!Ci`fE0fScJDAOc5B`I!Ci&!CbBdqrwjc ; %ngli%9 [email&#160;protected]!CbBdglbcvqcm ; %!Cb=!Fn!Cb>T!Cb<_>[!CbW!Cb;`z!Cb=U!Cb;^!Cb=`!Cb;!Fnz!Cb=U!Cb;^!Cb;`!Cb@!Fnz!Cb=S!Cb]!CbW!Cb<q><div class="clear">
                 
              
              
        
            </div></q></_>
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