PHP怎么返回整洁的结果
PHP如何返回整洁的结果?
我本来想在一个PHP返回json格式的,但是它把所有的warning也放进去了。
1 warning怎么关?
2 不关warning有其它办法吗,反正能返回纯洁点的结果 就好啦
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ini_set('display_errors', 0); // 关闭错误提示
不过warning级别的错误已经很严重了,应该想办法修复。
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php.ini中修改配置display_errors = Off或者在代码中加入error_reporting(0)可以禁止输出任何错误信息。
但既然出现了警告信息,就说明你的代码存在问题,最好还是根据提示信息找出报错原因并修正问题代码。
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你最好贴出报错信息。肯定是代码有问题了。
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谁让你出警告的,你按规范来写程序不就没有警告了?
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单独调试php,待无误后再联调
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error_reporting(0);
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Warning: Cannot modify header information - headers already sent by (output started at D:\wamp\www\include\log4php\LoggerLog.php:95) in D:\wamp\www\findtaxi\index.php on line 7
这个是错误的:请求头部【header("Content-Type:text/html;charset=UTF-8 ");】前面不能有其他东西,即使是空格空行也不行。
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Warning: LoggerOptionConverter::setProperty() No such setter method for [ConversionPattern] property in LoggerLayoutTTCC. in D:\wamp\www\include\log4php\LoggerLog.php on line 95
这个看看有没有这个,然后就是要注意大小写。看看大小写有木有问题。
------解决方案--------------------
Warning: LoggerOptionConverter::setProperty() No such setter method for [ConversionPattern] property in LoggerLayoutTTCC. in D:\wamp\www\include\log4php\LoggerLog.php on line 95
这个看看有没有,然后就是要注意大小写。看看大小写有木有问题。

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