php SQL判断字符串的步骤求解
php SQL判断字符串的方法求解
- SQL code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->$dsql->SetQuery("SELECT a.id,a.title,a.flag,b.aid,b.imgurl FROM `#@__archives` a Join `#@__addonarticle` b On a.id = b.aid where a.flag = 'f' ORDER BY a.id DESC LIMIT 0,4");以上 a.flag为字符串 在数据库中为 c,f,p,h,a
以上SQL查询flag为f没问题 请问怎么查询c,f或者c,f,p？ 另外c,f,p能不能打乱了写？
------解决方案--------------------
............a.flag like '%c,f%'
------解决方案--------------------
SQL判断字符串 .a.flag like '%c,f%'
------解决方案--------------------
str.a.flag like '%c,f%'就这样啊。很简单的
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