关于子网划分，子网掩码出现奇数的有关问题
关于子网划分，子网掩码出现奇数的问题
1.0.1.0--1.0.3.255 福建省 电信 转换为 1.0.1.0/24--1.0.2.0/23
上面是一个IP段，划分子网后得到后面的两个网段和子网掩码，如果用一般的方法，
把两个IP换成二进制进行异或预算
00000001.00000000.00000001.00000000
00000001.00000000.00000011.11111111
得到的子网掩码为
11111111.11111111.11111101.00000000
255.255.253.0
但是第三段 明显不符合连续一和连续零的规则，但是又不知道最上面的划分成两个网段的依据是什么，望高手解答，在线等，谢谢！
------解决方案--------------------
你是想搞懂原理还是有什么具体点的需求，说说先。
------解决方案--------------------
1.0.1.0--1.0.3.255 按 24 位掩码（C类网址） 划分，共 3 个网段
11111111 11111111 11111111 00000000 掩码
00000001 00000000 00000001 00000000 网段1
00000001 00000000 00000010 00000000 网段2
00000001 00000000 00000011 00000000 网段3
当掩码为 23 位时
11111111 11111111 11111110 00000000 掩码
分别于三个网段相与，得（红色部分）
00000001 00000000 00000001 00000000 网段1
00000001 00000000 00000000 00000000 结果1
00000001 00000000 00000010 00000000 网段2
00000001 00000000 00000010 00000000 结果2
00000001 00000000 00000011 00000000 网段3
00000001 00000000 00000010 00000000 结果3
很明显，结果2和结果3相等，所以是一个网段
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