可否在不继承一个类的时候执行一些方法
能否在不继承一个类的时候执行一些方法?
- PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->class a{ public $table = ''; public function __contruct($table) { $this->table=$table; }}class b{ $b = new a('abc');//Fatal error: Class 'a' not found}
能否使用别的什么方法代替?我现在想在b类里完成对a类构造函数的初始化
------解决方案--------------------
require_once ‘class_a_file.php’;
------解决方案--------------------
上面说的对,出错并不是不能new,而是class a的代码没加进来
我经常在一个类里面new另一个
------解决方案--------------------
------解决方案--------------------
取个例子,更好说明一些.
假设 class a 的代码存在 class_a.php class b 的代码存在class_b.php 上.
- PHP code
<?php function __autoload($class_name) { require("class_".$class_name.".php");}$b = new b(); //这样会自动去 加载 class_b.php 文件$a = new a(); //这样会自动去 加载 class_a.php 文件?><div class="clear"> </div>

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