可否在不继承一个类的时候执行一些方法

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Release: 2016-06-13 10:48:12
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能否在不继承一个类的时候执行一些方法?

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->class a{   public $table = '';   public function __contruct($table)   {       $this->table=$table;   }}class b{    $b = new a('abc');//Fatal error: Class 'a' not found}
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能否使用别的什么方法代替?我现在想在b类里完成对a类构造函数的初始化

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require_once ‘class_a_file.php’;
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上面说的对,出错并不是不能new,而是class a的代码没加进来

我经常在一个类里面new另一个
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探讨

靠,搜跌撕裂啊、我一直以为这个加载是应该让PHP从内部就给我完成的,没想到

------解决方案--------------------
取个例子,更好说明一些.
假设 class a 的代码存在 class_a.php class b 的代码存在class_b.php 上.
PHP code
<?php function __autoload($class_name) {      require("class_".$class_name.".php");}$b = new b(); //这样会自动去 加载 class_b.php 文件$a = new a(); //这样会自动去 加载  class_a.php 文件?><div class="clear">
                 
              
              
        
            </div>
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