请问怎么获取PHP页面中靠查询数据库后输出一个记录的表格中记录的状态
请教如何获取PHP页面中靠查询数据库后输出一个记录的表格中记录的状态?
如题,也就是有个表格是靠数据库输出的,多条记录中有个字段是是否支付,输出后怎样获取这个表格的项是否含有未支付的状态?
例如:
编号 名称 是否支付
1 苹果 已支付
2 香蕉 已支付
3 葡萄 已支付
这样的话就返回值为真,一个按钮可以点击。
如果:
例如:
编号 名称 是否支付
1 苹果 已支付
2 香蕉 已支付
3 葡萄 未支付
就返回假,这个按钮设置为不可以点击的状态。
请教,谢谢。
------解决方案--------------------
php输出mysql结果是靠数组,提取数组中是否支付的字段,挨个判断
按钮状态依照是否支付来决定
------解决方案--------------------
<br /> while($row=mysql_fetch_array($result)){<br /> $ar[]=$row["支付状态列"];<br /> }<br /> foreach($ar as $key=>$value){<br /> if($value=="未支付"){<br /> echo "<input type=\"button\" id=\"$key\" diabled=\"disabled\"/>";<br /> }else{<br /> echo "<input type=\"button\" id=\"$key\" \/>";<br /> }<br /> }<br />

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