Home Backend Development PHP Tutorial 请问怎么获取PHP页面中靠查询数据库后输出一个记录的表格中记录的状态

请问怎么获取PHP页面中靠查询数据库后输出一个记录的表格中记录的状态

Jun 13, 2016 am 11:11 AM
button input key mysql nbsp

请教如何获取PHP页面中靠查询数据库后输出一个记录的表格中记录的状态?
如题,也就是有个表格是靠数据库输出的,多条记录中有个字段是是否支付,输出后怎样获取这个表格的项是否含有未支付的状态?

例如:
编号 名称 是否支付
1    苹果 已支付
2    香蕉 已支付
3    葡萄 已支付

这样的话就返回值为真,一个按钮可以点击。

如果:

例如:
编号 名称 是否支付
1    苹果 已支付
2    香蕉 已支付
3    葡萄 未支付

就返回假,这个按钮设置为不可以点击的状态。

请教,谢谢。


------解决方案--------------------
php输出mysql结果是靠数组,提取数组中是否支付的字段,挨个判断

按钮状态依照是否支付来决定
------解决方案--------------------
<br />	while($row=mysql_fetch_array($result)){<br />		$ar[]=$row["支付状态列"];<br />	}<br />	foreach($ar as $key=>$value){<br />		if($value=="未支付"){<br />			echo "<input type=\"button\" id=\"$key\" diabled=\"disabled\"/>";<br />		}else{<br />			echo "<input type=\"button\" id=\"$key\" \/>";<br />		}<br />	}<br />
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