求解关于preg_replace函数解决思路

求解关于preg_replace函数
我想使用preg_replace函数把text里面的部分字符替换成图片
当我这样写时可以正常执行

<br />$expression ="[email&#160;protected]/";<br />$reexpression ="呲牙";<br />$text=preg_replace($expression,'<img  src="/static/imghw/default1.png"  data-src="www.test.com/static/expression/'.$reexpression.'.gif"  class="lazy"  .$reexpression.'.gif" / alt="求解关于preg_replace函数解决思路" > ',$text);

可是当我改成数组后替换后图片的url都成了www.test.com/static/expression/Array.gif了

<br />$expression =array("[email&#160;protected]/","[email&#160;protected]/","[email&#160;protected]/");<br />$reexpression =array("呲牙","鄙视","折磨");<br />$text=preg_replace($expression,'<img  src="/static/imghw/default1.png"  data-src="www.test.com/static/expression/'.$reexpression.'.gif"  class="lazy"  .$reexpression.'.gif" / alt="求解关于preg_replace函数解决思路" > ',$text);

我刚接触php，希望大家能帮忙看一下

------解决方案--------------------
在执行函数前会先计算出参数的值。因此也就是:
$replace = ' ';
$text = preg_replace($expression, $replace, $text);
// 由于 $reexpression 是个数组，因此数组和字符串相连就会是Array.gif

看你的需求，重新写一下:

$text = [email&#160;protected]，->@鄙视<-';<br />$reexpression =array("呲牙","鄙视","折磨");<br />// 希望你的程序最好以UTF-8编码，u修饰符的作用就是避免编码出现意外的混乱<br />$find = '#@('. join('<br><font color='#FF8000'>------解决方案--------------------</font><br>', $reexpression) .')#u';<br />$replace = '<img src="/static/imghw/default1.png"  data-src="www.test.com/static/expression/$1.gif"  class="lazy"   alt="$1"/>';<br />$text = preg_replace($find, $replace, $text);

另外你的图片以中文命名，还需要注意可能在IE下产生的编码问题，导致图片加载404错误

附手册： http://php.net/preg-replace

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