Home > php教程 > php手册 > body text

如何使用PHP实现javascript的escape和unescape函数

WBOY
Release: 2016-06-13 11:44:24
Original
1126 people have browsed it

前端开发工程师都知道javascript有编码函数escape()和对应的解码函数unescape(),而php中只有个urlencode和urldecode,这个编码和解码函数对encodeURI和encodeURIComponent有效,但是对escape的是无效的。
javascript中的escape()函数和unescape()函数用户字符串编码,类似于PHP中的urlencode()函数,下面是php实现的escape函数代码:

复制代码 代码如下:


/**
 * js escape php 实现
 * @param $string           the sting want to be escaped
 * @param $in_encoding      
 * @param $out_encoding     
 */
function escape($string, $in_encoding = 'UTF-8',$out_encoding = 'UCS-2') {
    $return = '';
    if (function_exists('mb_get_info')) {
        for($x = 0; $x             $str = mb_substr ( $string, $x, 1, $in_encoding );
            if (strlen ( $str ) > 1) { // 多字节字符
                $return .= '%u' . strtoupper ( bin2hex ( mb_convert_encoding ( $str, $out_encoding, $in_encoding ) ) );
            } else {
                $return .= '%' . strtoupper ( bin2hex ( $str ) );
            }
        }
    }
    return $return;
}


对应的解码php unescape代码是:

复制代码 代码如下:


function unescape($str)
{
    $ret = '';
    $len = strlen($str);
    for ($i = 0; $i     {
        if ($str[$i] == '%' && $str[$i + 1] == 'u')
        {
            $val = hexdec(substr($str, $i + 2, 4));
            if ($val                 $ret .= chr($val);
            else 
                if ($val                     $ret .= chr(0xc0 | ($val >> 6)) .
                     chr(0x80 | ($val & 0x3f));
                else
                    $ret .= chr(0xe0 | ($val >> 12)) .
                     chr(0x80 | (($val >> 6) & 0x3f)) .
                     chr(0x80 | ($val & 0x3f));
            $i += 5;
        } else 
            if ($str[$i] == '%')
            {
                $ret .= urldecode(substr($str, $i, 3));
                $i += 2;
            } else
                $ret .= $str[$i];
    }
    return $ret;
}


source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template